Probably the best way to keep track of this subtraction of the 6 from both sides is to format your work this way:

￼

What you see here is that I’ve subtracted 6 from both sides, drawn a horizontal “equals” bar underneath the entire equation, and then added down. On the left-hand side (LHS) of the equation, this gives me:

x plus nothing is x, and 6 minus 6 is zero

On the right-hand side (RHS) of the equation, I have:

–3 plus –6 is –9

The solution is the last line of my work; namely:

x = –9

The same “undo” procedure works for equations in which the variable has been paired with a subtraction.

Solve x – 3 = –5

The variable is on the left-hand side (LHS) of the equation, and it’s paired with a “subtract three”. Since I want to get x by itself, I don’t like the “3” that’s currently subtracted from it. The opposite of subtraction is addition, so I’ll undo the “subtract 3” by adding 3 to both sides of the equation, and then adding down to simplify to get my answer:

## Answers ( )

Step-by-step explanation:Probably the best way to keep track of this subtraction of the 6 from both sides is to format your work this way:

￼

What you see here is that I’ve subtracted 6 from both sides, drawn a horizontal “equals” bar underneath the entire equation, and then added down. On the left-hand side (LHS) of the equation, this gives me:

x plus nothing is x, and 6 minus 6 is zero

On the right-hand side (RHS) of the equation, I have:

–3 plus –6 is –9

The solution is the last line of my work; namely:

x = –9

The same “undo” procedure works for equations in which the variable has been paired with a subtraction.

Solve x – 3 = –5

The variable is on the left-hand side (LHS) of the equation, and it’s paired with a “subtract three”. Since I want to get x by itself, I don’t like the “3” that’s currently subtracted from it. The opposite of subtraction is addition, so I’ll undo the “subtract 3” by adding 3 to both sides of the equation, and then adding down to simplify to get my answer:

￼

Then my answer is:

x = –2